Problem 6 Find the critical value \(z_{\al... [FREE SOLUTION] (2024)

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Chapter 7: Problem 6

Find the critical value \(z_{\alpha / 2}\) that corresponds to the givenconfidence level. \(99 \%\)

Short Answer

Expert verified

The critical value \(z_{0.005}\) for a 99% confidence level is \(2.5758\).

Step by step solution

01

Understand the Confidence Level

The problem asks for the critical value corresponding to a 99% confidence level. This means that 99% of the data lies within the confidence interval, leaving 0.5% on each tail of the normal distribution.

02

Determine Alpha (\( \boldsymbol{\boldsymbol{\theta}} \boldsymbol{\boldsymbol{\theta}} \boldsymbol{\boldsymbol{\theta}}alpha\theta\boldsymbol{})).

The alpha (α) can be calculated by subtracting the confidence level from 1. This gives us: \(\theta = 1 - 0.99 = 0.01\). Therefore, for the two tails, \( \frac{\theta}{2} = 0.005\).

03

Use Standard Normal Distribution Table

Locate the critical value \(z_{\theta / 2}\) for the tail probability \(0.005\) in the standard normal distribution table (z-table). For \(z_{0.005}\), the corresponding z-value is \(2.5758\).

04

Interpret the Result

The critical value found from the z-table, \(2.5758\), represents the z-score where 0.5% of the distribution is beyond it in each tail, capturing 99% of the data within the interval.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Level

The confidence level, often expressed as a percentage, indicates how certain we can be that a parameter lies within the confidence interval derived from our sample data.
For example, a confidence level of 99% means that if we repeated an experiment or study 100 times, we would expect the true parameter to fall within the calculated interval 99 times out of 100.
Higher confidence levels provide more certainty but result in wider confidence intervals, while lower confidence levels generate narrower intervals.
This is essential when making decisions based on statistical data as it provides a measure of reliability for our estimates.

Alpha Level

The alpha level (α) is the probability of rejecting the null hypothesis when it is actually true. It's also known as the significance level and complements the confidence level.
Mathematically, the alpha level can be found by subtracting the confidence level from 1. For a 99% confidence level, the alpha level would be \(\theta = 1 - 0.99 = 0.01\).ewline The alpha level is then divided by 2, because it is split equally between the two tails of the normal distribution. So in this case, \(\frac{\theta}{2} = 0.005\).
It's used to determine critical values in hypothesis tests; small alpha levels mean stricter criteria for rejecting the null hypothesis, reducing the risk of Type I errors (false positives).

Normal Distribution

The normal distribution, often called the bell curve, is a continuous probability distribution that is symmetrical around the mean.
Most data points are concentrated around the mean, and the probabilities for values taper off as you move further from the mean.
In this distribution, approximately 68% of the data lies within one standard deviation from the mean, 95% within two, and 99.7% within three, following the Empirical Rule.
In our exercise, we use the normal distribution to determine critical values by locating specific z-scores that correspond to defined tail probabilities, like 0.005 for each tail in a 99% confidence level scenario.
These critical values help us capture the middle percentage of the data, giving us the z-scores needed for constructing confidence intervals.

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Problem 6 Find the critical value \(z_{\al... [FREE SOLUTION] (3)

Most popular questions from this chapter

A clinical trial was conducted to test the effectiveness of the drug zopiclonefor treating insomnia in older subjects. Before treatment with zopiclone, 16subjects had a mean wake time of \(102.8\) min. After treatment with zopiclone,the 16 subjects had a mean wake time of \(98.9\) min and a standard deviation of\(42.3\) min (based on data from "Cognitive Behavioral Therapy vs Zopiclone forTreatment of Chronic Primary Insomnia in Older Adults" by Sivertsen et al.,Journal of the American Medical Association, Vol. 295, No. 24 ). Assume thatthe 16 sample values appear to be from a normally distributed population andconstruct a \(98 \%\) confidence interval estimate of the mean wake time for apopulation with zopiclone treatments. What does the result suggest about themean wake time of \(102.8\) min before the treatment? Does zopiclone appear tobe effective?You are the operations manager for American Airlines and you are considering ahigher fare level for passengers in aisle seats. You want to estimate thepercentage of passengers who now prefer aisle seats. How many randomlyselected air passengers must you survey? Assume that you want to be \(95 \%\)confident that the sample percentage is within \(2.5\) percentage points of thetrue population percentage. a. Assume that nothing is known about the percentage of passengers who preferaisle seats. b. Assume that a prior survey suggests that about \(38 \%\) of air passengersprefer an aisle seat (based on a \(3 \mathrm{M}\) Privacy Filters survey).In clinical trials of the drug Lipitor (atorvastatin), 270 subjects were givena placebo and 7 of them had allergic reactions. Among 863 subjects treatedwith \(10 \mathrm{mg}\) of the drug, 8 experienced allergic reactions. Constructthe two \(95 \%\) confidence interval estimates of the percentages of allergicreactions. Compare the results. What do you conclude?What does it mean when we say that the confidence interval methods of thissection are robust against departures from normality?In a study of speed dating conducted at Columbia University, male subjectswere asked to rate the attractiveness of their female dates, and a sample ofthe results is listed below \((1=\) not attractive; \(10=\) extremely attractive).Construct a \(95 \%\) confidence interval estimate of the standard deviation ofthe population from which the sample was obtained.
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Problem 6 Find the critical value \(z_{\al... [FREE SOLUTION] (2024)

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